Let's Code

Link to the problem statement:   https://www.codechef.com/submit/DPOLY Solution:   #include <stdio.h> int main(void) { int t; scanf("%d", &t); while(t--) {     int i, n, d;     scanf("%d",  &n);     int a[n];     for(i=0;i<n;i++)     {         scanf("%d", &a[i]);         if(a[i] != 0)         {             d = i;         }              }     printf("%d\n", d); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:   codechef.com/submit/BATTERYLOW Solution:   #include <stdio.h> int main(void) { int t, x; scanf("%d", &t); while(t--) {     scanf("%d", &x);     if(x > 15)         printf("NO\n");     else         printf("YES\n"); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

    Link to the problem statement:   https://www.codechef.com/submit/FCTRL2 Solution:   The solution is already given, you just have to click on  SUBMIT CODE  button. //We have populated the solutions for the 10 easiest problems for your support. //Click on the SUBMIT button to make a submission to this problem. #include<stdio.h> int main() {     int t,n,a[200],i,j,k,l,m;     scanf("%d",&t);     while(t--)     {     scanf("%d",&n);         m=1;         a[0]=1;         for(j=2;j<=n;j++)         {             l=0;             for(k=0;k<m;k++)             {                 a[k]=a[k]*j+l;                 l=a[k]/10;         ...

  Link to the problem statement:  https://www.codechef.com/submit/INCRIQ Solution:   #include <stdio.h> int main(void) { int x;     scanf("%d",&x);     if(x>=100 && x <= 169)     {         if(x+7 > 170)             printf("YES\n");         else             printf("NO\n");     } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/TODOLIST Solution:   #include <stdio.h> int main(void) {     int t, n, i, j; scanf("%d", &t); for(i=0;i<t;i++) {     scanf("%d", &n);     int b=0, a[n];     for(j=0;j<n;j++)     {         scanf("%d", &a[j]);         if(a[j]>=1000)             b++;         else            continue;     }     printf("%d\n", b); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/COURSEREG Solution:   #include <stdio.h> int main(void) { int t, n, m, k; scanf("%d", &t); while(t--) {     scanf("%d %d %d", &n, &m, &k);     if(m-k >= n)         printf("Yes\n");     else         printf("No\n"); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/INTEST Solution:   The solution is already given, you just have to click on  SUBMIT CODE  button. //We have populated the solutions for the 10 easiest problems for your support. //Click on the SUBMIT button to make a submission to this problem. #include<stdio.h> int main() { int n,k,ans=0,i; scanf("%d %d",&n,&k); for(i=0;i<n;i++) { int t; scanf("%d",&t); if(t%k==0) { ans++; } } printf("%d",ans); return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/AIRHOCKEY Solution:   #include <stdio.h> int main(void) { int t, a, b; scanf("%d",&t); while(t--) {     scanf("%d %d", &a, &b);     if(a>b)     printf("%d\n", 7-a);     else     printf("%d\n", 7-b); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/FIT Solution:   #include <stdio.h> int main(void) { int t, x; scanf("%d",&t); while(t--) {     scanf("%d", &x);     x = x*10;     printf("%d\n", x); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/BIRYANI Solution:   #include <stdio.h> int main(void) { int t, x, y; scanf ("%d", &t); while(t--) {     scanf("%d %d", &x, &y);     x = x*y;     printf("%d\n",x); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

  Link to the problem statement:  https://www.codechef.com/submit/FLOW004 Solution:   The solution is already given, you just have to click on  SUBMIT CODE  button. //We have populated the solutions for the 10 easiest problems for your support. //Click on the SUBMIT button to make a submission to this problem. #include <stdio.h> int main() {     int ld,n,t,r;          scanf("%d",&t);     while(t--){         scanf("%d",&n);         ld = n%10;         while(n>0) {r=n%10; n/=10;}         printf("%d\n",r+ld);     }     return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit/CREDSCORE Solution:   #include <stdio.h> int main(void) { int t, i, x, y; scanf("%d", &t); for(i=0;i<t;i++) {     scanf("%d %d", &x, &y);     if(x >= y*30)     printf("YES\n");     else     printf("NO\n"); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit/BUDGET_ Solution:   #include <stdio.h> int main(void) { int t, i, x, y; scanf("%d", &t); for(i=0;i<t;i++) {     scanf("%d %d", &x, &y);     if(x >= y*30)     printf("YES\n");     else     printf("NO\n"); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit/INSTNOODLE Solution:   #include <stdio.h> int main(void) { int x, y; scanf("%d %d", &x, &y); x = x*y; printf("%d", x); return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit/FLOW006 Solution:   The solution is already given, you just have to click on  SUBMIT CODE  button. //We have populated the solutions for the 10 easiest problems for your support. //Click on the SUBMIT button to make a submission to this problem. #include <stdio.h> int main(void) { int t; scanf("%d",&t); while (t--){     int n,m,sum=0;     scanf ("%d",&n);     while(n>0){                  m=n%10;         n=n/10;              sum=sum+m;     }         printf("%d\n",sum); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit/TYRE Solution:   #include <stdio.h> int main(void) { int t, n, m; scanf("%d", &t); while(t--) {     scanf("%d %d", &n, &m);     n = 2*n + 4*m;     printf("%d\n", n); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit/EXPIRY Solution:   #include <stdio.h> int main(void) { int t, i, n, m, k; scanf("%d", &t); for(i=0;i<t;i++) {     scanf("%d %d %d", &n, &m, &k);     if(n <= (m*k))     printf("YES\n");     else     printf("NO\n"); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit-v2/LUCKYFR Solution:   #include <stdio.h> int main(void) { int t, i, x, k; scanf("%d", &t); for(i=0;i<t;i++) {     scanf("%d", &x);     k = 0;         while(x != 0)             {             if(x%10 == 4)                 k++;            x = x/10;         }     printf("%d\n", k); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit-v2/CHAIRS_ Solution:   #include <stdio.h> int main(void) { int t, i, x, y; scanf("%d",&t); for(i=0;i<t;i++) {     scanf("%d %d", &x, &y);     if(x<y)     printf("0\n");     else     {     x = x - y;     printf("%d\n", x);     } } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you  

Link to the problem statement:  https://www.codechef.com/submit-v2/CMASKS Solution:   #include <stdio.h> int main(void) { int t, i, x, y; scanf("%d", &t); for(i=0;i<t;i++) {     scanf("%d %d", &x, &y);     x = x*100;     y = y*10;     if(x > y || x == y)     printf("CLOTH\n");     else     printf("DISPOSABLE\n"); } return 0; } Hope this will help you, if you want anything else leave a comment. Thank you